Luis bought 5 scones and 2 large coffees for $16.74. Rachel bought 4 scones and 3 large coffees for $16.15. We are given that one scone costs $1.97. We want to find the cost of one large coffee.

AlgebraSystems of EquationsWord ProblemLinear Equations
2025/3/11

1. Problem Description

Luis bought 5 scones and 2 large coffees for $16.
7

4. Rachel bought 4 scones and 3 large coffees for $16.

1

5. We are given that one scone costs $1.

9

7. We want to find the cost of one large coffee.

2. Solution Steps

Let ss be the cost of one scone and cc be the cost of one large coffee.
We are given:
5s+2c=16.745s + 2c = 16.74
4s+3c=16.154s + 3c = 16.15
We are also given that s=1.97s = 1.97. Substituting this value into the two equations, we have:
5(1.97)+2c=16.745(1.97) + 2c = 16.74
4(1.97)+3c=16.154(1.97) + 3c = 16.15
Simplifying the first equation:
9.85+2c=16.749.85 + 2c = 16.74
2c=16.749.852c = 16.74 - 9.85
2c=6.892c = 6.89
c=6.892c = \frac{6.89}{2}
c=3.445c = 3.445
Simplifying the second equation:
7.88+3c=16.157.88 + 3c = 16.15
3c=16.157.883c = 16.15 - 7.88
3c=8.273c = 8.27
c=8.273c = \frac{8.27}{3}
c=2.75666...c = 2.75666...
We have two different values for cc, so we need to check the problem statement. We are given that one scone is 1.971.97. Substituting this value into the two equations:
Equation 1: 5s+2c=16.745s + 2c = 16.74
5(1.97)+2c=16.745(1.97) + 2c = 16.74
9.85+2c=16.749.85 + 2c = 16.74
2c=16.749.852c = 16.74 - 9.85
2c=6.892c = 6.89
c=6.89/2c = 6.89/2
c=3.445c = 3.445
Equation 2: 4s+3c=16.154s + 3c = 16.15
4(1.97)+3c=16.154(1.97) + 3c = 16.15
7.88+3c=16.157.88 + 3c = 16.15
3c=16.157.883c = 16.15 - 7.88
3c=8.273c = 8.27
c=8.27/3c = 8.27/3
c=2.756666...c = 2.756666...
There appears to be an inconsistency in the problem. Let us assume the cost of one scone is not exactly 1.
9

7. $5s + 2c = 16.74$

4s+3c=16.154s + 3c = 16.15
Multiply the first equation by 3 and the second by 2:
15s+6c=50.2215s + 6c = 50.22
8s+6c=32.308s + 6c = 32.30
Subtract the second equation from the first:
7s=17.927s = 17.92
s=17.92/7=2.56s = 17.92/7 = 2.56
Substitute s=2.56s = 2.56 into the first equation:
5(2.56)+2c=16.745(2.56) + 2c = 16.74
12.8+2c=16.7412.8 + 2c = 16.74
2c=16.7412.82c = 16.74 - 12.8
2c=3.942c = 3.94
c=3.94/2=1.97c = 3.94/2 = 1.97
However, we are given the cost of one scone is 1.971.97, not 2.562.56. The two given equations and the price of the scone are contradictory. Since we're given the price of the scone is 1.971.97, we can solve for the price of the coffee using the first equation.
5(1.97)+2c=16.745(1.97) + 2c = 16.74
9.85+2c=16.749.85 + 2c = 16.74
2c=16.749.85=6.892c = 16.74 - 9.85 = 6.89
c=6.89/2=3.445c = 6.89/2 = 3.445

3. Final Answer

The cost of one large coffee is $3.
4
4
5.

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