The problem is to analyze the equation $x^3 + y^3 = 3y$. We are asked to solve this equation. However, since no specific instructions are given (e.g., solve for $y$ in terms of $x$, or find integer solutions), we are simply rewriting the equation in different forms. It appears we're supposed to find the solutions to this equation. Without further information, finding all solutions can be complex. However, without additional instructions, let's rearrange this equation.

AlgebraCubic EquationsEquation SolvingVariables
2025/6/6

1. Problem Description

The problem is to analyze the equation x3+y3=3yx^3 + y^3 = 3y. We are asked to solve this equation. However, since no specific instructions are given (e.g., solve for yy in terms of xx, or find integer solutions), we are simply rewriting the equation in different forms. It appears we're supposed to find the solutions to this equation. Without further information, finding all solutions can be complex. However, without additional instructions, let's rearrange this equation.

2. Solution Steps

We can rearrange the given equation as follows:
x3+y3=3yx^3 + y^3 = 3y
x3+y33y=0x^3 + y^3 - 3y = 0
This equation relates xx and yy. Without additional context or constraints, we cannot obtain specific numerical solutions. We could express xx in terms of yy or yy in terms of xx, but that's not explicitly requested. Let us solve for x:
x3=3yy3x^3 = 3y - y^3
x=3yy33x = \sqrt[3]{3y - y^3}
Alternatively, let us see if we can factor x3+y33y=0x^3 + y^3 - 3y = 0. Factoring this cubic equation is difficult without knowing further constraints or having further instruction.

3. Final Answer

The equation can be rewritten as x3+y33y=0x^3 + y^3 - 3y = 0 or x=3yy33x = \sqrt[3]{3y - y^3}.
Final Answer: x=3yy33x = \sqrt[3]{3y - y^3}

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