The problem asks us to solve the given system of linear equations: $5x - 3y = 15$ $2x + y = -5$ using a graphing tool. Since we don't have access to the tool, we will solve it algebraically. The solution is the point of intersection of the two lines.

1. Problem Description

The problem asks us to solve the given system of linear equations:

$5x - 3y = 15$

$2x + y = -5$

using a graphing tool. Since we don't have access to the tool, we will solve it algebraically. The solution is the point of intersection of the two lines.

2. Solution Steps

We can use the substitution or elimination method to solve the system. Let's use the substitution method.

First, solve the second equation for $y$:

$2x + y = -5$

$y = -2x - 5$

Now, substitute this expression for $y$ into the first equation:

$5x - 3(-2x - 5) = 15$

$5x + 6x + 15 = 15$

$11x + 15 = 15$

$11x = 0$

$x = 0$

Now, substitute $x = 0$ back into the equation $y = -2x - 5$:

$y = -2(0) - 5$

$y = -5$

So the solution is $x = 0$ and $y = -5$. The point of intersection is $(0, -5)$.

3. Final Answer

The solution to the system of equations is $(0, -5)$.