Question 9: Find the binary, hexadecimal, or octal number that is equivalent to the decimal value 161. Question 10: Find the number with the least value among a binary, a decimal, a hexadecimal, and an octal number.

Number TheoryNumber Base ConversionsBinaryHexadecimalOctalDecimal
2025/4/8
Here are the solutions to questions 9 and
1
0.

1. Problem Description

Question 9: Find the binary, hexadecimal, or octal number that is equivalent to the decimal value
1
6

1. Question 10: Find the number with the least value among a binary, a decimal, a hexadecimal, and an octal number.

2. Solution Steps

Question 9:
Convert each option to decimal to check for equivalence.
1) 111110002=127+126+125+124+123+022+021+020=128+64+32+16+8=24811111000_2 = 1 \cdot 2^7 + 1 \cdot 2^6 + 1 \cdot 2^5 + 1 \cdot 2^4 + 1 \cdot 2^3 + 0 \cdot 2^2 + 0 \cdot 2^1 + 0 \cdot 2^0 = 128 + 64 + 32 + 16 + 8 = 248
2) 101000012=127+026+125+024+023+022+021+120=128+32+1=16110100001_2 = 1 \cdot 2^7 + 0 \cdot 2^6 + 1 \cdot 2^5 + 0 \cdot 2^4 + 0 \cdot 2^3 + 0 \cdot 2^2 + 0 \cdot 2^1 + 1 \cdot 2^0 = 128 + 32 + 1 = 161
3) A216=10161+2160=160+2=162A2_{16} = 10 \cdot 16^1 + 2 \cdot 16^0 = 160 + 2 = 162
4) 5108=582+181+080=564+8+0=320+8=328510_8 = 5 \cdot 8^2 + 1 \cdot 8^1 + 0 \cdot 8^0 = 5 \cdot 64 + 8 + 0 = 320 + 8 = 328
Question 10:
Convert each option to decimal to compare their values.
1) 11000112=126+125+024+023+022+121+120=64+32+2+1=991100011_2 = 1 \cdot 2^6 + 1 \cdot 2^5 + 0 \cdot 2^4 + 0 \cdot 2^3 + 0 \cdot 2^2 + 1 \cdot 2^1 + 1 \cdot 2^0 = 64 + 32 + 2 + 1 = 99
2) 12010=120120_{10} = 120
3) FE16=15161+14160=240+14=254FE_{16} = 15 \cdot 16^1 + 14 \cdot 16^0 = 240 + 14 = 254
4) 678=681+780=48+7=5567_8 = 6 \cdot 8^1 + 7 \cdot 8^0 = 48 + 7 = 55
The least value is
5
5.

3. Final Answer

Question 9: 2) 101000012
Question 10: 4) 678

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