(a) A manufacturing company requires 3 hours of direct labor to process every $N87.00$ worth of raw materials. If the company uses $N30,450.00$ worth of raw materials, what amount should it budget for direct labor at $N18.25$ per hour? (b) An investor invested $Nx$ in bank $M$ at the rate of $6\%$ simple interest per annum and $Ny$ in bank $N$ at the rate of $8\%$ simple interest per annum. If a total of $N8,000,000.00$ was invested in the two banks and the investor received a total of $N2,320,000.00$ as interest from the two banks after 4 years, calculate: (i) the values of $x$ and $y$; (ii) the interest paid by the second bank.

AlgebraWord ProblemsLinear EquationsSimple InterestRatio and Proportion
2025/4/10

1. Problem Description

(a) A manufacturing company requires 3 hours of direct labor to process every N87.00N87.00 worth of raw materials. If the company uses N30,450.00N30,450.00 worth of raw materials, what amount should it budget for direct labor at N18.25N18.25 per hour?
(b) An investor invested NxNx in bank MM at the rate of 6%6\% simple interest per annum and NyNy in bank NN at the rate of 8%8\% simple interest per annum. If a total of N8,000,000.00N8,000,000.00 was invested in the two banks and the investor received a total of N2,320,000.00N2,320,000.00 as interest from the two banks after 4 years, calculate:
(i) the values of xx and yy;
(ii) the interest paid by the second bank.

2. Solution Steps

(a)
First, we need to find out how many multiples of N87.00N87.00 are in N30,450.00N30,450.00.
Number of multiples =3045087=350= \frac{30450}{87} = 350.
Since each N87.00N87.00 requires 3 hours of direct labor, N30,450.00N30,450.00 requires 350×3=1050350 \times 3 = 1050 hours of direct labor.
The cost of direct labor per hour is N18.25N18.25.
Total cost of direct labor =1050×18.25=19162.50= 1050 \times 18.25 = 19162.50.
(b)
(i) Let the amount invested in bank MM be xx and the amount invested in bank NN be yy.
We are given that the total investment is N8,000,000.00N8,000,000.00, so:
x+y=8,000,000x + y = 8,000,000 --- (1)
The interest rate for bank MM is 6%6\% and for bank NN is 8%8\%. The total interest received after 4 years is N2,320,000.00N2,320,000.00.
The simple interest formula is:
Interest=Principal×Rate×TimeInterest = Principal \times Rate \times Time
Interest=PRTInterest = PRT
Interest from bank M=x×0.06×4=0.24xM = x \times 0.06 \times 4 = 0.24x
Interest from bank N=y×0.08×4=0.32yN = y \times 0.08 \times 4 = 0.32y
Total interest =0.24x+0.32y=2,320,000= 0.24x + 0.32y = 2,320,000 --- (2)
From equation (1), we have x=8,000,000yx = 8,000,000 - y. Substitute this into equation (2):
0.24(8,000,000y)+0.32y=2,320,0000.24(8,000,000 - y) + 0.32y = 2,320,000
1,920,0000.24y+0.32y=2,320,0001,920,000 - 0.24y + 0.32y = 2,320,000
0.08y=2,320,0001,920,0000.08y = 2,320,000 - 1,920,000
0.08y=400,0000.08y = 400,000
y=400,0000.08=5,000,000y = \frac{400,000}{0.08} = 5,000,000
Substitute y=5,000,000y = 5,000,000 into equation (1):
x+5,000,000=8,000,000x + 5,000,000 = 8,000,000
x=8,000,0005,000,000=3,000,000x = 8,000,000 - 5,000,000 = 3,000,000
So, x=3,000,000x = 3,000,000 and y=5,000,000y = 5,000,000.
(ii) The interest paid by the second bank (bank NN) is:
Interest=y×0.08×4=5,000,000×0.08×4=5,000,000×0.32=1,600,000Interest = y \times 0.08 \times 4 = 5,000,000 \times 0.08 \times 4 = 5,000,000 \times 0.32 = 1,600,000

3. Final Answer

(a) The company should budget N19,162.50N19,162.50 for direct labor.
(b)
(i) x=N3,000,000.00x = N3,000,000.00 and y=N5,000,000.00y = N5,000,000.00
(ii) The interest paid by the second bank is N1,600,000.00N1,600,000.00

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