The problem provides a function $f(x) = 93\log d + 65$ that relates the speed of the wind, $f(x)$, in miles per hour near the center of a tornado to the distance $d$ that a tornado travels in miles. Given that a tornado has sustained winds of 400 mph, we need to estimate the distance it can travel.

AlgebraLogarithmsEquation SolvingWord Problem
2025/4/10

1. Problem Description

The problem provides a function f(x)=93logd+65f(x) = 93\log d + 65 that relates the speed of the wind, f(x)f(x), in miles per hour near the center of a tornado to the distance dd that a tornado travels in miles. Given that a tornado has sustained winds of 400 mph, we need to estimate the distance it can travel.

2. Solution Steps

We are given the function f(x)=93logd+65f(x) = 93\log d + 65 and f(x)=400f(x) = 400. We need to solve for dd.
400=93logd+65400 = 93\log d + 65
Subtract 65 from both sides:
40065=93logd400 - 65 = 93\log d
335=93logd335 = 93\log d
Divide by 93:
33593=logd\frac{335}{93} = \log d
To solve for dd, we need to use the property that if logd=x\log d = x, then d=10xd = 10^x.
d=1033593d = 10^{\frac{335}{93}}
d103.602d \approx 10^{3.602}
d4000d \approx 4000

3. Final Answer

4000 miles

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