The problem asks to express the equation $27^{\frac{1}{3}} = 3$ in logarithmic form.

1. Problem Description

The problem asks to express the equation $27^{\frac{1}{3}} = 3$ in logarithmic form.

2. Solution Steps

The general form of an exponential equation is $b^x = y$, where $b$ is the base, $x$ is the exponent, and $y$ is the result.

The logarithmic form of the exponential equation $b^x = y$ is $\log_b y = x$.

In the given equation, $27^{\frac{1}{3}} = 3$, we have $b=27$, $x = \frac{1}{3}$, and $y = 3$.

Therefore, the logarithmic form is $\log_{27} 3 = \frac{1}{3}$.

3. Final Answer

$\log_{27} 3 = \frac{1}{3}$