The problem asks to evaluate the expression $\log_m{m^{2n}}$.

AlgebraLogarithmsExponent PropertiesSimplification
2025/4/10

1. Problem Description

The problem asks to evaluate the expression logmm2n\log_m{m^{2n}}.

2. Solution Steps

We can use the property of logarithms that states logaax=x\log_a{a^x} = x. In this case, we have a=ma = m and x=2nx = 2n. Therefore,
logmm2n=2n\log_m{m^{2n}} = 2n.

3. Final Answer

2n

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