The problem asks us to find the measure of angle T in the given trapezoid TVZY. The trapezoid has TV parallel to YZ, and TV = YZ. Also, angle V is given as 60 degrees.

1. Problem Description

The problem asks us to find the measure of angle T in the given trapezoid TVZY. The trapezoid has TV parallel to YZ, and TV = YZ. Also, angle V is given as 60 degrees.

2. Solution Steps

Since TVZY is a trapezoid with TV parallel to YZ and TV = YZ, it is an isosceles trapezoid. In an isosceles trapezoid, the base angles are equal. Therefore, $m\angle V = m\angle Z$.

Since $m\angle V = 60^\circ$, then $m\angle Z = 60^\circ$.

Also, in an isosceles trapezoid, adjacent angles between the parallel sides are supplementary. Therefore, $m\angle V + m\angle Y = 180^\circ$ and $m\angle T + m\angle Z = 180^\circ$.

Since $m\angle V = 60^\circ$, we have $60^\circ + m\angle Y = 180^\circ$, so $m\angle Y = 180^\circ - 60^\circ = 120^\circ$.

Since $m\angle Z = 60^\circ$, we have $m\angle T + 60^\circ = 180^\circ$, so $m\angle T = 180^\circ - 60^\circ = 120^\circ$.

3. Final Answer

The measure of angle T is 120 degrees.