We are given a diagram with two parallel lines intersected by two transversals. We need to find the value of $x + y$.

GeometryParallel LinesTransversalsAnglesSupplementary Angles
2025/4/11

1. Problem Description

We are given a diagram with two parallel lines intersected by two transversals. We need to find the value of x+yx + y.

2. Solution Steps

Since the two horizontal lines are parallel, we can use properties of angles formed by parallel lines and transversals.
The angle vertically opposite to 3535^{\circ} is also 3535^{\circ}. Since this 3535^{\circ} angle and yy are supplementary angles, we have:
y+35=180y + 35^{\circ} = 180^{\circ}
y=18035y = 180^{\circ} - 35^{\circ}
y=145y = 145^{\circ}
The angle vertically opposite to 110110^{\circ} is also 110110^{\circ}. Since this 110110^{\circ} angle and xx are supplementary angles, we have:
x+110=180x + 110^{\circ} = 180^{\circ}
x=180110x = 180^{\circ} - 110^{\circ}
x=70x = 70^{\circ}
Now we can calculate x+yx+y:
x+y=70+145=215x + y = 70^{\circ} + 145^{\circ} = 215^{\circ}

3. Final Answer

x+y=215x + y = 215^{\circ}
The answer is A.

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