The problem states that 500 tickets were sold for a concert. Adult tickets cost \$4.50 and children's tickets cost \$3.00. The total revenue from ticket sales was \$1987.50. The question asks how many adult tickets were sold.

AlgebraLinear EquationsSystems of EquationsWord Problem
2025/4/11

1. Problem Description

The problem states that 500 tickets were sold for a concert. Adult tickets cost \4.50 and children's tickets cost \3.
0

0. The total revenue from ticket sales was \$1987.

5

0. The question asks how many adult tickets were sold.

2. Solution Steps

Let aa be the number of adult tickets sold and cc be the number of children's tickets sold.
We can set up a system of two equations with two variables.
The first equation represents the total number of tickets sold:
a+c=500a + c = 500
The second equation represents the total revenue from ticket sales:
4.50a+3.00c=1987.504.50a + 3.00c = 1987.50
We can solve for cc in the first equation:
c=500ac = 500 - a
Substitute this expression for cc into the second equation:
4.50a+3.00(500a)=1987.504.50a + 3.00(500 - a) = 1987.50
4.50a+15003.00a=1987.504.50a + 1500 - 3.00a = 1987.50
1.50a=1987.5015001.50a = 1987.50 - 1500
1.50a=487.501.50a = 487.50
a=487.501.50a = \frac{487.50}{1.50}
a=325a = 325
Now we can find the number of children's tickets sold:
c=500a=500325=175c = 500 - a = 500 - 325 = 175
The number of adult tickets sold is
3
2
5.

3. Final Answer

The number of adult tickets sold is
3
2

5. Answer: A. 325

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