We are given a quadrilateral $QRST$. We are asked to find the lengths of the sides $TS$ and $QR$. We are given the coordinates of $T(-3, 2)$. From the figure, we can determine the coordinates of the other vertices.

GeometryCoordinate GeometryDistance FormulaQuadrilateral2D Geometry
2025/3/13

1. Problem Description

We are given a quadrilateral QRSTQRST.
We are asked to find the lengths of the sides TSTS and QRQR. We are given the coordinates of T(3,2)T(-3, 2). From the figure, we can determine the coordinates of the other vertices.

2. Solution Steps

From the graph:
Q(1,3)Q(1, 3)
R(1,1)R(1, -1)
S(3,1)S(-3, -1)
T(3,2)T(-3, 2)
To find the length of TSTS, we use the distance formula:
d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}.
TS=(3(3))2+(2(1))2TS = \sqrt{(-3 - (-3))^2 + (2 - (-1))^2}
TS=(0)2+(3)2TS = \sqrt{(0)^2 + (3)^2}
TS=0+9TS = \sqrt{0 + 9}
TS=9TS = \sqrt{9}
TS=3TS = 3
To find the length of QRQR, we use the distance formula:
d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}.
QR=(11)2+(3(1))2QR = \sqrt{(1 - 1)^2 + (3 - (-1))^2}
QR=(0)2+(4)2QR = \sqrt{(0)^2 + (4)^2}
QR=0+16QR = \sqrt{0 + 16}
QR=16QR = \sqrt{16}
QR=4QR = 4

3. Final Answer

Length of TSTS: 3
Length of QRQR: 4

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