The problem asks us to expand the expression $(1 - 4m)(m^2 - 3m + 8)$ and write the answer as a polynomial in standard form.

AlgebraPolynomialsExpansionDistributionCombining Like Terms
2025/3/14

1. Problem Description

The problem asks us to expand the expression (14m)(m23m+8)(1 - 4m)(m^2 - 3m + 8) and write the answer as a polynomial in standard form.

2. Solution Steps

First, we distribute the terms in the first parenthesis to the terms in the second parenthesis:
(14m)(m23m+8)=1(m23m+8)4m(m23m+8)(1 - 4m)(m^2 - 3m + 8) = 1(m^2 - 3m + 8) - 4m(m^2 - 3m + 8)
Next, we distribute the 11 and 4m-4m:
1(m23m+8)=m23m+81(m^2 - 3m + 8) = m^2 - 3m + 8
4m(m23m+8)=4m3+12m232m-4m(m^2 - 3m + 8) = -4m^3 + 12m^2 - 32m
Now, we add the two resulting polynomials:
(m23m+8)+(4m3+12m232m)=4m3+(m2+12m2)+(3m32m)+8(m^2 - 3m + 8) + (-4m^3 + 12m^2 - 32m) = -4m^3 + (m^2 + 12m^2) + (-3m - 32m) + 8
Combining like terms:
4m3+13m235m+8-4m^3 + 13m^2 - 35m + 8

3. Final Answer

The final answer is 4m3+13m235m+8-4m^3 + 13m^2 - 35m + 8.

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