We need to simplify the expression $\sqrt[5]{1024x^{10}y^{11}}$, assuming that all variables are nonnegative real numbers.

AlgebraSimplificationRadicalsExponentsAlgebraic Expressions
2025/4/15

1. Problem Description

We need to simplify the expression 1024x10y115\sqrt[5]{1024x^{10}y^{11}}, assuming that all variables are nonnegative real numbers.

2. Solution Steps

We want to simplify the expression 1024x10y115\sqrt[5]{1024x^{10}y^{11}}.
First, we express 1024 as a power of 2: 1024=2101024 = 2^{10}.
So, we have 210x10y115\sqrt[5]{2^{10}x^{10}y^{11}}.
Next, we rewrite the expression using fractional exponents:
(210x10y11)15(2^{10}x^{10}y^{11})^{\frac{1}{5}}
Then we apply the power rule:
2105x105y1152^{\frac{10}{5}}x^{\frac{10}{5}}y^{\frac{11}{5}}
Simplify the exponents:
22x2y1152^2 x^2 y^{\frac{11}{5}}
Rewrite y115y^{\frac{11}{5}} as y105+15=y105y15=y2y15y^{\frac{10}{5} + \frac{1}{5}} = y^{\frac{10}{5}} y^{\frac{1}{5}} = y^2 y^{\frac{1}{5}}.
The expression now is:
22x2y2y152^2 x^2 y^2 y^{\frac{1}{5}}
22=42^2 = 4, so we have
4x2y2y154x^2y^2 y^{\frac{1}{5}}
Rewrite y15y^{\frac{1}{5}} as y5\sqrt[5]{y}.
So, the final expression is:
4x2y2y54x^2y^2 \sqrt[5]{y}

3. Final Answer

4x2y2y54x^2y^2\sqrt[5]{y}

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