The problem asks us to find the inverse of the function $f(x) = 2x + 3$.

AlgebraFunctionsInverse FunctionsLinear Functions
2025/4/21

1. Problem Description

The problem asks us to find the inverse of the function f(x)=2x+3f(x) = 2x + 3.

2. Solution Steps

To find the inverse of a function, we can follow these steps:

1. Replace $f(x)$ with $y$.

2. Swap $x$ and $y$.

3. Solve for $y$.

4. Replace $y$ with $f^{-1}(x)$.

Step 1: Replace f(x)f(x) with yy.
y=2x+3y = 2x + 3
Step 2: Swap xx and yy.
x=2y+3x = 2y + 3
Step 3: Solve for yy.
x3=2yx - 3 = 2y
y=x32y = \frac{x - 3}{2}
Step 4: Replace yy with f1(x)f^{-1}(x).
f1(x)=x32f^{-1}(x) = \frac{x - 3}{2}

3. Final Answer

The inverse of the function f(x)=2x+3f(x) = 2x + 3 is f1(x)=x32f^{-1}(x) = \frac{x - 3}{2}.

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