The problem asks to simplify the expression $\sqrt{12} + \sqrt{75} - 2\sqrt{108}$.

AlgebraRadicalsSimplificationSquare RootsAlgebraic Manipulation
2025/4/15

1. Problem Description

The problem asks to simplify the expression 12+752108\sqrt{12} + \sqrt{75} - 2\sqrt{108}.

2. Solution Steps

First, simplify each radical term:
12=43=43=23\sqrt{12} = \sqrt{4 \cdot 3} = \sqrt{4} \cdot \sqrt{3} = 2\sqrt{3}
75=253=253=53\sqrt{75} = \sqrt{25 \cdot 3} = \sqrt{25} \cdot \sqrt{3} = 5\sqrt{3}
108=363=363=63\sqrt{108} = \sqrt{36 \cdot 3} = \sqrt{36} \cdot \sqrt{3} = 6\sqrt{3}
Substitute the simplified radicals back into the original expression:
12+752108=23+532(63)\sqrt{12} + \sqrt{75} - 2\sqrt{108} = 2\sqrt{3} + 5\sqrt{3} - 2(6\sqrt{3})
=23+53123= 2\sqrt{3} + 5\sqrt{3} - 12\sqrt{3}
Combine the terms with 3\sqrt{3}:
=(2+512)3= (2 + 5 - 12)\sqrt{3}
=(712)3= (7 - 12)\sqrt{3}
=53= -5\sqrt{3}

3. Final Answer

The final answer is 53-5\sqrt{3}.

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