The problem asks us to simplify the expression $(\sqrt{8x-3}+3)^2$, assuming that all variables represent nonnegative numbers.

AlgebraAlgebraic SimplificationRadicalsBinomial Expansion
2025/4/15

1. Problem Description

The problem asks us to simplify the expression (8x3+3)2(\sqrt{8x-3}+3)^2, assuming that all variables represent nonnegative numbers.

2. Solution Steps

We need to expand the square of the binomial. Recall the formula:
(a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2
In our case, a=8x3a = \sqrt{8x-3} and b=3b = 3.
So, we have
(8x3+3)2=(8x3)2+2(8x3)(3)+32(\sqrt{8x-3}+3)^2 = (\sqrt{8x-3})^2 + 2(\sqrt{8x-3})(3) + 3^2
(8x3)2=8x3(\sqrt{8x-3})^2 = 8x-3
2(8x3)(3)=68x32(\sqrt{8x-3})(3) = 6\sqrt{8x-3}
32=93^2 = 9
Therefore,
(8x3+3)2=8x3+68x3+9(\sqrt{8x-3}+3)^2 = 8x-3 + 6\sqrt{8x-3} + 9
Combining like terms, we get
(8x3+3)2=8x+6+68x3(\sqrt{8x-3}+3)^2 = 8x + 6 + 6\sqrt{8x-3}

3. Final Answer

8x+6+68x38x+6+6\sqrt{8x-3}

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