We are asked to find a quadratic equation in the standard form $ax^2 + bx + c = 0$ with integer coefficients $a$, $b$, and $c$ such that $a$ is positive and $a, b, c$ have no common factor, and the given solutions are $11$ and $-13$.

AlgebraQuadratic EquationsRoots of PolynomialsFactoringInteger Coefficients
2025/4/15

1. Problem Description

We are asked to find a quadratic equation in the standard form ax2+bx+c=0ax^2 + bx + c = 0 with integer coefficients aa, bb, and cc such that aa is positive and a,b,ca, b, c have no common factor, and the given solutions are 1111 and 13-13.

2. Solution Steps

Since the solutions are x=11x = 11 and x=13x = -13, the factors of the quadratic equation are (x11)(x - 11) and (x(13))=(x+13)(x - (-13)) = (x + 13). Therefore, we can write the quadratic equation as:
(x11)(x+13)=0(x - 11)(x + 13) = 0
Expanding the expression, we have:
x2+13x11x1113=0x^2 + 13x - 11x - 11 \cdot 13 = 0
x2+2x143=0x^2 + 2x - 143 = 0
The coefficients are a=1a = 1, b=2b = 2, and c=143c = -143. Since aa is positive and the greatest common divisor of 1, 2, and -143 is 1, the equation is in the required form.

3. Final Answer

The quadratic equation is x2+2x143=0x^2 + 2x - 143 = 0.

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