A container is initially $\frac{2}{5}$ full of fruit juice. 700 ml of water is added, and the container becomes $\frac{3}{4}$ full. We need to find: (i) the fraction of the container's capacity that corresponds to the added water. (ii) the fraction of the container's capacity that is separated if $\frac{4}{5}$ of the fruit drink is separated out. (iii) the amount of drink in one glass, if the separated amount is poured into 6 glasses equally. (iv) the amount of fruit drink remaining in the container.

AlgebraWord ProblemFractionsLinear EquationsPercentagesVolume
2025/3/16

1. Problem Description

A container is initially 25\frac{2}{5} full of fruit juice. 700 ml of water is added, and the container becomes 34\frac{3}{4} full. We need to find:
(i) the fraction of the container's capacity that corresponds to the added water.
(ii) the fraction of the container's capacity that is separated if 45\frac{4}{5} of the fruit drink is separated out.
(iii) the amount of drink in one glass, if the separated amount is poured into 6 glasses equally.
(iv) the amount of fruit drink remaining in the container.

2. Solution Steps

(i) Let the capacity of the container be CC. Initially, the container has 25C\frac{2}{5}C of fruit juice. After adding 700 ml of water, the container is 34\frac{3}{4} full. Therefore,
25C+700=34C \frac{2}{5}C + 700 = \frac{3}{4}C
34C25C=700 \frac{3}{4}C - \frac{2}{5}C = 700
15820C=700 \frac{15 - 8}{20}C = 700
720C=700 \frac{7}{20}C = 700
C=207×700=20×100=2000 ml C = \frac{20}{7} \times 700 = 20 \times 100 = 2000 \text{ ml}
The capacity of the container is 2000 ml.
The fraction of the container's capacity that corresponds to the 700 ml of water is:
7002000=720 \frac{700}{2000} = \frac{7}{20}
(ii) The initial amount of fruit juice is 25C=25×2000=800\frac{2}{5}C = \frac{2}{5} \times 2000 = 800 ml.
If 45\frac{4}{5} of the fruit drink is separated, the amount separated is 45×800=640\frac{4}{5} \times 800 = 640 ml.
The fraction of the container's capacity that the separated amount represents is:
6402000=64200=32100=825 \frac{640}{2000} = \frac{64}{200} = \frac{32}{100} = \frac{8}{25}
(iii) The separated amount of drink is 640 ml. This is poured into 6 glasses equally. The amount of drink in one glass is:
6406=3203=10623 ml \frac{640}{6} = \frac{320}{3} = 106\frac{2}{3} \text{ ml}
(iv) The initial amount of fruit juice is 800 ml. The amount separated is 640 ml. The amount of fruit drink remaining is:
800640=160 ml 800 - 640 = 160 \text{ ml}

3. Final Answer

(i) The fraction of the capacity of the container that is the amount of water that was added is 720\frac{7}{20}.
(ii) The fraction of the capacity of the container that is the separated amount of drink is 825\frac{8}{25}.
(iii) The amount of drink in one glass is 3203\frac{320}{3} ml or 10623106\frac{2}{3} ml.
(iv) The amount of fruit drink remaining in the container is 160 ml.

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