We are given a graph of an exponential function of the form $y = a + 2^{x+b}$. We need to find the equation of the graph based on the given points on the graph, which are $(0, -1)$, $(1, 1)$, and $(2, 5)$. We need to find the values of $a$ and $b$.

AlgebraExponential FunctionsEquation SolvingSubstitutionCoordinate Geometry
2025/3/16

1. Problem Description

We are given a graph of an exponential function of the form y=a+2x+by = a + 2^{x+b}. We need to find the equation of the graph based on the given points on the graph, which are (0,1)(0, -1), (1,1)(1, 1), and (2,5)(2, 5). We need to find the values of aa and bb.

2. Solution Steps

Let's use the points (0,1)(0, -1) and (1,1)(1, 1) to find the values of aa and bb.
Plugging (0,1)(0, -1) into the equation gives:
1=a+20+b-1 = a + 2^{0+b}
1=a+2b-1 = a + 2^b
a=12ba = -1 - 2^b (1)
Plugging (1,1)(1, 1) into the equation gives:
1=a+21+b1 = a + 2^{1+b} (2)
Substitute (1) into (2):
1=(12b)+21+b1 = (-1 - 2^b) + 2^{1+b}
1=12b+22b1 = -1 - 2^b + 2 \cdot 2^b
2=2b2 = 2^b
21=2b2^1 = 2^b
b=1b = 1
Substitute b=1b = 1 into (1):
a=121a = -1 - 2^1
a=12a = -1 - 2
a=3a = -3
So the equation is y=3+2x+1y = -3 + 2^{x+1}.
Let's check with the point (2,5)(2, 5):
y=3+22+1y = -3 + 2^{2+1}
y=3+23y = -3 + 2^3
y=3+8y = -3 + 8
y=5y = 5
This confirms that the equation is correct.

3. Final Answer

The equation of the graph is y=3+2x+1y = -3 + 2^{x+1}.
Therefore, the answer is C. y=3+2x+1y = -3 + 2^{x+1}.

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