The problem is to simplify the expression $\frac{1}{3}a^2b - \frac{3}{5}ab^2 + \frac{3}{8}a^2b - \frac{5}{3}ab$.

AlgebraPolynomialsSimplificationAlgebraic ExpressionsCombining Like TermsFractions
2025/4/21

1. Problem Description

The problem is to simplify the expression 13a2b35ab2+38a2b53ab\frac{1}{3}a^2b - \frac{3}{5}ab^2 + \frac{3}{8}a^2b - \frac{5}{3}ab.

2. Solution Steps

First, we need to identify the like terms in the expression. The terms 13a2b\frac{1}{3}a^2b and 38a2b\frac{3}{8}a^2b are like terms because they have the same variables raised to the same powers (a2ba^2b). Also note that the term 53ab\frac{-5}{3}ab seems to have no other like terms, and likewise 35ab2\frac{-3}{5}ab^2 appears to have no other like terms.
Now, we combine the like terms:
13a2b+38a2b=(13+38)a2b\frac{1}{3}a^2b + \frac{3}{8}a^2b = (\frac{1}{3} + \frac{3}{8})a^2b
To add the fractions 13\frac{1}{3} and 38\frac{3}{8}, we need to find a common denominator, which is
2

4. $\frac{1}{3} = \frac{1 \cdot 8}{3 \cdot 8} = \frac{8}{24}$

38=3383=924\frac{3}{8} = \frac{3 \cdot 3}{8 \cdot 3} = \frac{9}{24}
So, 13+38=824+924=8+924=1724\frac{1}{3} + \frac{3}{8} = \frac{8}{24} + \frac{9}{24} = \frac{8+9}{24} = \frac{17}{24}
Therefore, 13a2b+38a2b=1724a2b\frac{1}{3}a^2b + \frac{3}{8}a^2b = \frac{17}{24}a^2b.
Now, rewrite the entire expression with the simplified like terms:
1724a2b35ab253ab\frac{17}{24}a^2b - \frac{3}{5}ab^2 - \frac{5}{3}ab

3. Final Answer

The simplified expression is 1724a2b35ab253ab\frac{17}{24}a^2b - \frac{3}{5}ab^2 - \frac{5}{3}ab.

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