The problem presents three logarithmic equations: 1. $\log_4 x = 2$

AlgebraLogarithmsExponential EquationsEquation Solving
2025/4/22

1. Problem Description

The problem presents three logarithmic equations:

1. $\log_4 x = 2$

2. $\log_5 x = 4$

3. $\log_2 25 = 2$

We are asked to solve for xx in the first two equations. The third equation is incorrect, as log2252\log_2 25 \neq 2. However, we only need to solve for xx in the first two equations.

2. Solution Steps

Equation 1: log4x=2\log_4 x = 2
To solve for xx, we can rewrite the logarithmic equation in exponential form. The general form is logba=cbc=a\log_b a = c \Rightarrow b^c = a. In this case, we have:
42=x4^2 = x
x=16x = 16
Equation 2: log5x=4\log_5 x = 4
Similarly, we can rewrite this logarithmic equation in exponential form:
54=x5^4 = x
x=5×5×5×5x = 5 \times 5 \times 5 \times 5
x=25×25x = 25 \times 25
x=625x = 625

3. Final Answer

The solution to the first equation, log4x=2\log_4 x = 2, is x=16x = 16.
The solution to the second equation, log5x=4\log_5 x = 4, is x=625x = 625.

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