The problem provides the formula $\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2}$ and asks to solve for $R_1$ in part (a) and for $R_2$ in part (b).

AlgebraEquation SolvingFormula ManipulationReciprocals
2025/5/2

1. Problem Description

The problem provides the formula 1RT=1R1+1R2\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} and asks to solve for R1R_1 in part (a) and for R2R_2 in part (b).

2. Solution Steps

(a) Solving for R1R_1:
First, isolate the term with R1R_1 by subtracting 1R2\frac{1}{R_2} from both sides of the equation:
1RT1R2=1R1\frac{1}{R_T} - \frac{1}{R_2} = \frac{1}{R_1}
Now, find a common denominator for the left side:
R2RTRTR2=1R1\frac{R_2 - R_T}{R_T R_2} = \frac{1}{R_1}
Next, take the reciprocal of both sides to solve for R1R_1:
R1=RTR2R2RTR_1 = \frac{R_T R_2}{R_2 - R_T}
(b) Solving for R2R_2:
First, isolate the term with R2R_2 by subtracting 1R1\frac{1}{R_1} from both sides of the equation:
1RT1R1=1R2\frac{1}{R_T} - \frac{1}{R_1} = \frac{1}{R_2}
Now, find a common denominator for the left side:
R1RTRTR1=1R2\frac{R_1 - R_T}{R_T R_1} = \frac{1}{R_2}
Next, take the reciprocal of both sides to solve for R2R_2:
R2=RTR1R1RTR_2 = \frac{R_T R_1}{R_1 - R_T}

3. Final Answer

(a) R1=RTR2R2RTR_1 = \frac{R_T R_2}{R_2 - R_T}
(b) R2=RTR1R1RTR_2 = \frac{R_T R_1}{R_1 - R_T}

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