We are given two equations: $x - y = -1$ $-1 = x^3 + 1$ We need to solve for $x$ and $y$.

AlgebraSystems of EquationsCubic EquationsSolving EquationsCube Root
2025/5/4

1. Problem Description

We are given two equations:
xy=1x - y = -1
1=x3+1-1 = x^3 + 1
We need to solve for xx and yy.

2. Solution Steps

First, let's solve the second equation for xx:
1=x3+1-1 = x^3 + 1
Subtract 1 from both sides:
11=x3+11-1 - 1 = x^3 + 1 - 1
2=x3-2 = x^3
Take the cube root of both sides:
x=23x = \sqrt[3]{-2}
Now, let's substitute the value of xx into the first equation:
xy=1x - y = -1
23y=1\sqrt[3]{-2} - y = -1
Add yy and 11 to both sides:
23+1=y\sqrt[3]{-2} + 1 = y
y=1+23y = 1 + \sqrt[3]{-2}
y=123y = 1 - \sqrt[3]{2}

3. Final Answer

x=23x = \sqrt[3]{-2}
y=123y = 1 - \sqrt[3]{2}

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