The problem asks to multiply two matrices: a 1x3 matrix and a 3x1 matrix. We need to calculate the resulting 1x1 matrix. The given matrices are $\begin{bmatrix} 3 & 4 & 5 \end{bmatrix}$ and $\begin{bmatrix} 5 \\ 6 \\ 7 \end{bmatrix}$.

AlgebraMatrix MultiplicationLinear AlgebraDot Product
2025/3/6

1. Problem Description

The problem asks to multiply two matrices: a 1x3 matrix and a 3x1 matrix. We need to calculate the resulting 1x1 matrix. The given matrices are [345]\begin{bmatrix} 3 & 4 & 5 \end{bmatrix} and [567]\begin{bmatrix} 5 \\ 6 \\ 7 \end{bmatrix}.

2. Solution Steps

The multiplication of two matrices AA and BB, where AA is an m×nm \times n matrix and BB is an n×pn \times p matrix, results in an m×pm \times p matrix. In this case, we have a 1×31 \times 3 matrix multiplied by a 3×13 \times 1 matrix, resulting in a 1×11 \times 1 matrix (a scalar).
To find the element in the resulting matrix, we perform the dot product of the row of the first matrix and the column of the second matrix:
C11=(3)(5)+(4)(6)+(5)(7)C_{11} = (3)(5) + (4)(6) + (5)(7)
C11=15+24+35C_{11} = 15 + 24 + 35
C11=74C_{11} = 74
Since the result is a 1x1 matrix, the only element is
7
4.

3. Final Answer

7474

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