We are given a system of two equations with two variables, $x$ and $y$: $4x - 2y = 20$ $x - 2y = -10$ We need to find the $y$-intercept of the first equation, $4x - 2y = 20$. The $x$-intercept of the first equation is already given, $x=5$.

1. Problem Description

We are given a system of two equations with two variables, $x$ and $y$:

$4x - 2y = 20$

$x - 2y = -10$

We need to find the $y$-intercept of the first equation, $4x - 2y = 20$. The $x$-intercept of the first equation is already given, $x=5$.

2. Solution Steps

To find the $y$-intercept of the first equation, we need to set $x=0$ and solve for $y$.

So, we substitute $x=0$ into the equation $4x - 2y = 20$:

$4(0) - 2y = 20$

$0 - 2y = 20$

$-2y = 20$

$y = \frac{20}{-2}$

$y = -10$

Therefore, the $y$-intercept of the first equation is $-10$.

3. Final Answer

$y = -10$