We are asked to solve the following system of linear equations: $8x - 4y = 6$ $12x - 6y = 9$ If there is no solution, we should enter "NO SOLUTION".

1. Problem Description

We are asked to solve the following system of linear equations:

$8x - 4y = 6$

$12x - 6y = 9$

If there is no solution, we should enter "NO SOLUTION".

2. Solution Steps

First, let's simplify the given equations:

$8x - 4y = 6$ can be simplified by dividing both sides by 2:

$4x - 2y = 3$ (Equation 1)

$12x - 6y = 9$ can be simplified by dividing both sides by 3:

$4x - 2y = 3$ (Equation 2)

Notice that both equations are the same. This means that the system is dependent, and there are infinitely many solutions. To express the solution, we can solve for $y$ in terms of $x$ (or vice-versa).

From the equation $4x - 2y = 3$, we can solve for $y$:

$2y = 4x - 3$

$y = \frac{4x - 3}{2}$

$y = 2x - \frac{3}{2}$

The solution set can be expressed as $(x, 2x - \frac{3}{2})$.

3. Final Answer

$(x, y) = (x, 2x - \frac{3}{2})$