The problem states that $y$ varies directly as the square of $x$. We are given that $y=4$ when $x=1$. We are asked to find something, but it is cut off from the image. It's likely asking us to find the equation relating $y$ and $x$, or to find the value of $y$ for a given $x$, or vice versa. I will assume the problem asks to find the equation relating $y$ and $x$.

AlgebraDirect VariationProportionalityEquations
2025/3/20

1. Problem Description

The problem states that yy varies directly as the square of xx. We are given that y=4y=4 when x=1x=1. We are asked to find something, but it is cut off from the image. It's likely asking us to find the equation relating yy and xx, or to find the value of yy for a given xx, or vice versa. I will assume the problem asks to find the equation relating yy and xx.

2. Solution Steps

Since yy varies directly as the square of xx, we can write the relationship as:
y=kx2y = kx^2
where kk is the constant of proportionality.
We are given that y=4y=4 when x=1x=1. We can substitute these values into the equation to find kk:
4=k(1)24 = k(1)^2
4=k(1)4 = k(1)
k=4k = 4
Therefore, the equation relating yy and xx is:
y=4x2y = 4x^2

3. Final Answer

The equation relating yy and xx is y=4x2y = 4x^2.

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