We are given the expression for $y'(x)$ and are asked to simplify it. The expression is $y'(x) = \frac{x^2 + 1}{x}$.

1. Problem Description

We are given the expression for $y'(x)$ and are asked to simplify it.

The expression is $y'(x) = \frac{x^2 + 1}{x}$.

2. Solution Steps

We can simplify the expression by dividing each term in the numerator by the denominator:

$y'(x) = \frac{x^2}{x} + \frac{1}{x}$.

Simplifying each term, we have:

$y'(x) = x + \frac{1}{x}$.

We can also write $\frac{1}{x}$ as $x^{-1}$. Therefore, we have:

$y'(x) = x + x^{-1}$.

3. Final Answer

$y'(x) = x + \frac{1}{x}$