The problem is to solve the inequality $6 \le 3n$ for $n$. We are also given a potential solution $n=4$. We need to verify this is correct.

AlgebraInequalitiesSolving InequalitiesLinear InequalitiesVariable IsolationSolution Verification
2025/5/7

1. Problem Description

The problem is to solve the inequality 63n6 \le 3n for nn. We are also given a potential solution n=4n=4. We need to verify this is correct.

2. Solution Steps

We have the inequality 63n6 \le 3n. To solve for nn, we need to isolate nn on one side of the inequality. We can do this by dividing both sides of the inequality by
3.
63n6 \le 3n
633n3\frac{6}{3} \le \frac{3n}{3}
2n2 \le n
n2n \ge 2
The solution to the inequality is n2n \ge 2. Now, let's test the given value, n=4n = 4.
If n=4n = 4, then 3n=3(4)=123n = 3(4) = 12.
Since 6126 \le 12, the value n=4n=4 is a valid solution because 424 \ge 2. In fact, any value of nn greater or equal to 2 is a valid solution.

3. Final Answer

n2n \ge 2 and n=4n=4 is one possible solution.

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