The problem shows the function $f(x) = 5 \cdot 2^x$ and an empty coordinate plane. The goal is to plot the function on the coordinate plane. However, since plotting the function is not possible within this context, I will provide some key points to sketch the graph of the function.

1. Problem Description

The problem shows the function $f(x) = 5 \cdot 2^x$ and an empty coordinate plane. The goal is to plot the function on the coordinate plane. However, since plotting the function is not possible within this context, I will provide some key points to sketch the graph of the function.

2. Solution Steps

First, let's calculate the values of the function for a few values of $x$:

- When $x = 0$, $f(0) = 5 \cdot 2^0 = 5 \cdot 1 = 5$.

- When $x = 1$, $f(1) = 5 \cdot 2^1 = 5 \cdot 2 = 10$.

- When $x = 2$, $f(2) = 5 \cdot 2^2 = 5 \cdot 4 = 20$.

- When $x = -1$, $f(-1) = 5 \cdot 2^{-1} = 5 \cdot (1/2) = 2.5$.

- When $x = -2$, $f(-2) = 5 \cdot 2^{-2} = 5 \cdot (1/4) = 1.25$.

Thus, the following points are on the graph of $f(x)$:

$(0, 5)$, $(1, 10)$, $(2, 20)$, $(-1, 2.5)$, $(-2, 1.25)$.

The function $f(x) = 5 \cdot 2^x$ is an exponential function. It passes through $(0,5)$. As $x$ increases, $f(x)$ increases exponentially. As $x$ approaches $-\infty$, $f(x)$ approaches

0.

3. Final Answer

Key points on the graph are (0, 5), (1, 10), (2, 20), (-1, 2.5), and (-2, 1.25). The function is an exponential function, approaching 0 as x approaches $-\infty$, and increasing rapidly as x increases.