The problem provides the exponential function $f(x) = 2 \cdot 3^x$. We are given a graph and are expected to plot the function $f(x)$.

AlgebraExponential FunctionsGraphingFunction AnalysisAsymptotes
2025/5/7

1. Problem Description

The problem provides the exponential function f(x)=23xf(x) = 2 \cdot 3^x. We are given a graph and are expected to plot the function f(x)f(x).

2. Solution Steps

To sketch the graph, we can calculate the value of the function for some xx values:
If x=0x = 0, then f(0)=230=21=2f(0) = 2 \cdot 3^0 = 2 \cdot 1 = 2. Thus, the point (0,2)(0, 2) is on the graph.
If x=1x = 1, then f(1)=231=23=6f(1) = 2 \cdot 3^1 = 2 \cdot 3 = 6. Thus, the point (1,6)(1, 6) is on the graph.
If x=2x = 2, then f(2)=232=29=18f(2) = 2 \cdot 3^2 = 2 \cdot 9 = 18. Thus, the point (2,18)(2, 18) is on the graph.
If x=1x = -1, then f(1)=231=213=230.67f(-1) = 2 \cdot 3^{-1} = 2 \cdot \frac{1}{3} = \frac{2}{3} \approx 0.67. Thus, the point (1,23)(-1, \frac{2}{3}) is on the graph.
If x=2x = -2, then f(2)=232=219=290.22f(-2) = 2 \cdot 3^{-2} = 2 \cdot \frac{1}{9} = \frac{2}{9} \approx 0.22. Thus, the point (2,29)(-2, \frac{2}{9}) is on the graph.
The function is an exponential growth function. As xx gets larger, f(x)f(x) grows rapidly. As xx approaches -\infty, f(x)f(x) approaches

0. Plotting the points $(0, 2)$, $(1, 6)$, $(2, 18)$, $(-1, \frac{2}{3})$ on the graph and sketching the exponential curve should give a good representation of the graph of $f(x) = 2 \cdot 3^x$.

3. Final Answer

The graph of f(x)=23xf(x) = 2 \cdot 3^x is an exponential curve passing through (0,2)(0, 2), (1,6)(1, 6) and (2,18)(2, 18). As x approaches negative infinity, the curve gets closer to the x-axis, which is the asymptote for this function.

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