The problem asks us to analyze the given exponential function $y = 5 \cdot (\frac{1}{2})^x$ and graph it on the provided coordinate plane.

AlgebraExponential FunctionsGraphingFunction Analysis
2025/5/7

1. Problem Description

The problem asks us to analyze the given exponential function y=5(12)xy = 5 \cdot (\frac{1}{2})^x and graph it on the provided coordinate plane.

2. Solution Steps

To graph the function y=5(12)xy = 5 \cdot (\frac{1}{2})^x, we can first find some points by substituting different values of xx into the equation.
When x=0x = 0, y=5(12)0=51=5y = 5 \cdot (\frac{1}{2})^0 = 5 \cdot 1 = 5. So, the point (0, 5) is on the graph.
When x=1x = 1, y=5(12)1=512=2.5y = 5 \cdot (\frac{1}{2})^1 = 5 \cdot \frac{1}{2} = 2.5. So, the point (1, 2.5) is on the graph.
When x=2x = 2, y=5(12)2=514=1.25y = 5 \cdot (\frac{1}{2})^2 = 5 \cdot \frac{1}{4} = 1.25. So, the point (2, 1.25) is on the graph.
When x=1x = -1, y=5(12)1=52=10y = 5 \cdot (\frac{1}{2})^{-1} = 5 \cdot 2 = 10. So, the point (-1, 10) is on the graph.
When x=2x = -2, y=5(12)2=54=20y = 5 \cdot (\frac{1}{2})^{-2} = 5 \cdot 4 = 20. So, the point (-2, 20) is on the graph.
Plot these points on the graph and draw a smooth curve through them. This curve represents the exponential function.

3. Final Answer

The graph is a decreasing exponential curve that passes through the points (0, 5), (1, 2.5), (2, 1.25), (-1, 10), and (-2, 20).

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