The problem is to determine the equation of the line shown in the graph.

AlgebraLinear EquationsSlope-intercept formCoordinate Geometry
2025/3/7

1. Problem Description

The problem is to determine the equation of the line shown in the graph.

2. Solution Steps

First, we identify two points on the line from the graph. It looks like the line passes through (0,2)(0, 2) and (4,4)(4, -4).
We can calculate the slope mm of the line using the formula:
m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
Using the two points (0,2)(0, 2) and (4,4)(4, -4), we have x1=0x_1 = 0, y1=2y_1 = 2, x2=4x_2 = 4, and y2=4y_2 = -4.
Therefore,
m=4240=64=32m = \frac{-4 - 2}{4 - 0} = \frac{-6}{4} = -\frac{3}{2}.
The equation of the line can be written in slope-intercept form as y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
We already found the slope m=32m = -\frac{3}{2}. From the graph, we can see that the line intersects the y-axis at y=2y=2, so the y-intercept b=2b = 2.
Therefore, the equation of the line is y=32x+2y = -\frac{3}{2}x + 2.

3. Final Answer

y=32x+2y = -\frac{3}{2}x + 2

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