We are given the polynomial function $h(x) = 2x^4 - x^3 + 2x^2 - 6x - 5$, and we are asked to evaluate $h(-2)$.

AlgebraPolynomial EvaluationPolynomials
2025/3/20

1. Problem Description

We are given the polynomial function h(x)=2x4x3+2x26x5h(x) = 2x^4 - x^3 + 2x^2 - 6x - 5, and we are asked to evaluate h(2)h(-2).

2. Solution Steps

We substitute x=2x = -2 into the polynomial:
h(2)=2(2)4(2)3+2(2)26(2)5h(-2) = 2(-2)^4 - (-2)^3 + 2(-2)^2 - 6(-2) - 5
h(2)=2(16)(8)+2(4)(12)5h(-2) = 2(16) - (-8) + 2(4) - (-12) - 5
h(2)=32+8+8+125h(-2) = 32 + 8 + 8 + 12 - 5
h(2)=40+8+125h(-2) = 40 + 8 + 12 - 5
h(2)=48+125h(-2) = 48 + 12 - 5
h(2)=605h(-2) = 60 - 5
h(2)=55h(-2) = 55

3. Final Answer

The final answer is 55.

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