We are given that $x=2$ is a root of the equation $4x^3 + kx - 24 = 0$. We need to find the value of $k$.

AlgebraPolynomial EquationsRoot of an EquationSubstitutionSolving for a Variable
2025/3/20

1. Problem Description

We are given that x=2x=2 is a root of the equation 4x3+kx24=04x^3 + kx - 24 = 0. We need to find the value of kk.

2. Solution Steps

Since x=2x=2 is a root of the equation 4x3+kx24=04x^3 + kx - 24 = 0, we can substitute x=2x=2 into the equation and solve for kk.
Substituting x=2x=2 into the equation gives us:
4(2)3+k(2)24=04(2)^3 + k(2) - 24 = 0
4(8)+2k24=04(8) + 2k - 24 = 0
32+2k24=032 + 2k - 24 = 0
8+2k=08 + 2k = 0
2k=82k = -8
k=82k = \frac{-8}{2}
k=4k = -4

3. Final Answer

The value of kk is 4-4.

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