The problem asks to determine the completely factored form of the polynomial $f(x) = x^3 + 5x^2 - x - 5$.

AlgebraPolynomial FactorizationFactoring by GroupingDifference of SquaresCubic Polynomials
2025/3/20

1. Problem Description

The problem asks to determine the completely factored form of the polynomial f(x)=x3+5x2x5f(x) = x^3 + 5x^2 - x - 5.

2. Solution Steps

We can factor the polynomial by grouping.
f(x)=x3+5x2x5f(x) = x^3 + 5x^2 - x - 5
f(x)=(x3+5x2)+(x5)f(x) = (x^3 + 5x^2) + (-x - 5)
f(x)=x2(x+5)1(x+5)f(x) = x^2(x + 5) - 1(x + 5)
f(x)=(x21)(x+5)f(x) = (x^2 - 1)(x + 5)
We can further factor x21x^2 - 1 using the difference of squares formula:
a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b).
Thus, x21=(x1)(x+1)x^2 - 1 = (x - 1)(x + 1).
Therefore, f(x)=(x1)(x+1)(x+5)f(x) = (x - 1)(x + 1)(x + 5).

3. Final Answer

(x+5)(x+1)(x1)(x+5)(x+1)(x-1)

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