We are asked to find the remainder when the polynomial $x^2 + 3x$ is divided by $x$.

AlgebraPolynomial DivisionRemainder TheoremPolynomial Factorization
2025/3/20

1. Problem Description

We are asked to find the remainder when the polynomial x2+3xx^2 + 3x is divided by xx.

2. Solution Steps

To find the remainder when x2+3xx^2 + 3x is divided by xx, we can perform polynomial long division or simply factor out xx from the expression x2+3xx^2 + 3x.
Factoring out xx, we have:
x2+3x=x(x+3)x^2 + 3x = x(x + 3)
This means that x2+3xx^2 + 3x can be written as xx multiplied by (x+3)(x + 3). Since x2+3x=x(x+3)+0x^2 + 3x = x(x+3) + 0, the quotient is x+3x+3 and the remainder is 00.
Alternatively, we can perform polynomial long division.
x + 3
x | x^2 + 3x
- (x^2)
3x
- (3x)
0
The remainder is 00.

3. Final Answer

0

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