We are asked to solve the quadratic equation $x^2 - 9x + 20 = 0$ by graphing. This means we want to find the $x$-intercepts of the graph of the quadratic function $y = x^2 - 9x + 20$.

AlgebraQuadratic EquationsRoots of EquationFactoringGraphing
2025/3/7

1. Problem Description

We are asked to solve the quadratic equation x29x+20=0x^2 - 9x + 20 = 0 by graphing. This means we want to find the xx-intercepts of the graph of the quadratic function y=x29x+20y = x^2 - 9x + 20.

2. Solution Steps

First, we can create a table of values for y=x29x+20y = x^2 - 9x + 20:
x | y
---|---
3 | 329(3)+20=927+20=23^2 - 9(3) + 20 = 9 - 27 + 20 = 2
4 | 429(4)+20=1636+20=04^2 - 9(4) + 20 = 16 - 36 + 20 = 0
5 | 529(5)+20=2545+20=05^2 - 9(5) + 20 = 25 - 45 + 20 = 0
6 | 629(6)+20=3654+20=26^2 - 9(6) + 20 = 36 - 54 + 20 = 2
From the table, we can see that the function has roots at x=4x=4 and x=5x=5. These are the xx-intercepts of the graph. We can also solve this by factoring the quadratic:
x29x+20=(x4)(x5)=0x^2 - 9x + 20 = (x-4)(x-5) = 0.
Therefore x4=0x-4 = 0 or x5=0x-5 = 0, so x=4x=4 or x=5x=5.

3. Final Answer

x=4,5x = 4, 5

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