The problem states that a set of 3 consecutive integers sums to 87. We need to find the value of the greatest integer.

AlgebraInteger EquationsConsecutive IntegersLinear Equations
2025/5/12

1. Problem Description

The problem states that a set of 3 consecutive integers sums to
8

7. We need to find the value of the greatest integer.

2. Solution Steps

Let the three consecutive integers be xx, x+1x+1, and x+2x+2.
The sum of these integers is x+(x+1)+(x+2)=87x + (x+1) + (x+2) = 87.
Combining like terms, we get 3x+3=873x + 3 = 87.
Subtracting 3 from both sides, we have 3x=8733x = 87 - 3, so 3x=843x = 84.
Dividing both sides by 3, we get x=843=28x = \frac{84}{3} = 28.
The three consecutive integers are 28, 29, and
3

0. The greatest integer is $x+2 = 28 + 2 = 30$.

3. Final Answer

30

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