Find the values of $c$ and $d$ that satisfy the equation $7 \times 10^c + 7 \times 10^d = 70700$.

AlgebraExponentsEquationsSolving EquationsPowers of 10
2025/6/14

1. Problem Description

Find the values of cc and dd that satisfy the equation 7×10c+7×10d=707007 \times 10^c + 7 \times 10^d = 70700.

2. Solution Steps

We are given the equation 7×10c+7×10d=707007 \times 10^c + 7 \times 10^d = 70700.
We can divide both sides of the equation by 7:
7×10c+7×10d7=707007\frac{7 \times 10^c + 7 \times 10^d}{7} = \frac{70700}{7}
10c+10d=1010010^c + 10^d = 10100
We can rewrite 1010010100 as 10000+10010000 + 100, which are powers of 10:
10100=104+10210100 = 10^4 + 10^2
Therefore, 10c+10d=104+10210^c + 10^d = 10^4 + 10^2.
We can conclude that cc and dd are 4 and 2, respectively. Since the order does not matter, we can have c=4c=4 and d=2d=2, or c=2c=2 and d=4d=4.

3. Final Answer

c=4,d=2c = 4, d = 2 or c=2,d=4c = 2, d = 4

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