We are asked to find the equation of a line that passes through the point $(4, 5)$ and is parallel to the line $y = x - 1$. The answer choices are given as multiple choice options.

AlgebraLinear EquationsParallel LinesSlope-intercept formCoordinate Geometry
2025/3/22

1. Problem Description

We are asked to find the equation of a line that passes through the point (4,5)(4, 5) and is parallel to the line y=x1y = x - 1. The answer choices are given as multiple choice options.

2. Solution Steps

The equation of a line can be written in the slope-intercept form as:
y=mx+by = mx + b
where mm is the slope and bb is the y-intercept.
Since the line we are looking for is parallel to the line y=x1y = x - 1, the slope of our line is the same as the slope of the given line. In the equation y=x1y = x - 1, the coefficient of xx is 11, so the slope is m=1m = 1.
Thus, the equation of our line is of the form y=1x+by = 1x + b, or y=x+by = x + b.
We are given that the line passes through the point (4,5)(4, 5). This means that when x=4x = 4, y=5y = 5. We can substitute these values into our equation to solve for bb:
5=4+b5 = 4 + b
b=54b = 5 - 4
b=1b = 1
Therefore, the equation of the line is y=x+1y = x + 1.

3. Final Answer

The equation of the line is y=x+1y = x + 1. The answer is (b).

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