The problem defines two functions $f(x) = 3x^2 - 1$ and $g(x) = 3 - x^2$. We need to find the value of $(g \circ f)(1)$ and choose the correct option among the given choices.

AlgebraFunction CompositionPolynomial FunctionsEvaluation
2025/3/22

1. Problem Description

The problem defines two functions f(x)=3x21f(x) = 3x^2 - 1 and g(x)=3x2g(x) = 3 - x^2. We need to find the value of (gf)(1)(g \circ f)(1) and choose the correct option among the given choices.

2. Solution Steps

First, we need to find the value of f(1)f(1).
f(x)=3x21f(x) = 3x^2 - 1
f(1)=3(1)21=3(1)1=31=2f(1) = 3(1)^2 - 1 = 3(1) - 1 = 3 - 1 = 2
Next, we need to find the value of g(f(1))g(f(1)), which is g(2)g(2).
g(x)=3x2g(x) = 3 - x^2
g(2)=3(2)2=34=1g(2) = 3 - (2)^2 = 3 - 4 = -1
Therefore, (gf)(1)=g(f(1))=g(2)=1(g \circ f)(1) = g(f(1)) = g(2) = -1.

3. Final Answer

B. (gf)(1)=1(g \circ f)(1) = -1

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