The problem asks us to solve a first-order linear differential equation using Bernoulli's method. The image does not contain the actual differential equation, only the description. Therefore, I will provide a general solution strategy for solving a first-order differential equation with Bernoulli's method. We consider the general form: $\frac{dy}{dx} + P(x)y = Q(x)y^n$ where $n$ is a real number and $n \neq 0, 1$.

AnalysisDifferential EquationsBernoulli EquationFirst-Order Differential EquationsSolution Methods
2025/5/18

1. Problem Description

The problem asks us to solve a first-order linear differential equation using Bernoulli's method. The image does not contain the actual differential equation, only the description. Therefore, I will provide a general solution strategy for solving a first-order differential equation with Bernoulli's method. We consider the general form:
dydx+P(x)y=Q(x)yn\frac{dy}{dx} + P(x)y = Q(x)y^n
where nn is a real number and n0,1n \neq 0, 1.

2. Solution Steps

Step 1: Divide the equation by yny^n:
yndydx+P(x)y1n=Q(x)y^{-n} \frac{dy}{dx} + P(x)y^{1-n} = Q(x)
Step 2: Make the substitution z=y1nz = y^{1-n}.
Then dzdx=(1n)yndydx\frac{dz}{dx} = (1-n) y^{-n} \frac{dy}{dx}.
Therefore, yndydx=11ndzdxy^{-n} \frac{dy}{dx} = \frac{1}{1-n} \frac{dz}{dx}.
Step 3: Substitute these into the equation:
11ndzdx+P(x)z=Q(x)\frac{1}{1-n} \frac{dz}{dx} + P(x)z = Q(x)
Multiply by (1n)(1-n):
dzdx+(1n)P(x)z=(1n)Q(x)\frac{dz}{dx} + (1-n)P(x)z = (1-n)Q(x)
This is a first-order linear differential equation in zz.
Step 4: Find the integrating factor μ(x)\mu(x):
μ(x)=e(1n)P(x)dx\mu(x) = e^{\int (1-n)P(x) dx}
Step 5: Multiply the equation by μ(x)\mu(x):
μ(x)dzdx+μ(x)(1n)P(x)z=μ(x)(1n)Q(x)\mu(x) \frac{dz}{dx} + \mu(x)(1-n)P(x)z = \mu(x)(1-n)Q(x)
Step 6: Observe that the left side is the derivative of μ(x)z\mu(x)z:
ddx(μ(x)z)=μ(x)(1n)Q(x)\frac{d}{dx}(\mu(x)z) = \mu(x)(1-n)Q(x)
Step 7: Integrate both sides with respect to xx:
ddx(μ(x)z)dx=μ(x)(1n)Q(x)dx\int \frac{d}{dx}(\mu(x)z) dx = \int \mu(x)(1-n)Q(x) dx
μ(x)z=μ(x)(1n)Q(x)dx+C\mu(x)z = \int \mu(x)(1-n)Q(x) dx + C
Step 8: Solve for zz:
z=1μ(x)μ(x)(1n)Q(x)dx+Cμ(x)z = \frac{1}{\mu(x)} \int \mu(x)(1-n)Q(x) dx + \frac{C}{\mu(x)}
Step 9: Substitute back z=y1nz = y^{1-n}:
y1n=1μ(x)μ(x)(1n)Q(x)dx+Cμ(x)y^{1-n} = \frac{1}{\mu(x)} \int \mu(x)(1-n)Q(x) dx + \frac{C}{\mu(x)}
Finally, solve for yy:
y=(1μ(x)μ(x)(1n)Q(x)dx+Cμ(x))11ny = \left( \frac{1}{\mu(x)} \int \mu(x)(1-n)Q(x) dx + \frac{C}{\mu(x)} \right)^{\frac{1}{1-n}}

3. Final Answer

The general solution to the Bernoulli differential equation dydx+P(x)y=Q(x)yn\frac{dy}{dx} + P(x)y = Q(x)y^n is:
y=(1μ(x)μ(x)(1n)Q(x)dx+Cμ(x))11ny = \left( \frac{1}{\mu(x)} \int \mu(x)(1-n)Q(x) dx + \frac{C}{\mu(x)} \right)^{\frac{1}{1-n}}, where μ(x)=e(1n)P(x)dx\mu(x) = e^{\int (1-n)P(x) dx}.

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