The problem describes the constraints on a student's work hours and earnings at a college. Students can work no more than 20 hours per week and can earn a maximum of $320 per week. The jobs pay different rates, starting from $8.75 per hour. We need to write two inequalities representing these constraints and define the variables used.

AlgebraInequalitiesWord ProblemsLinear InequalitiesConstraints
2025/3/25

1. Problem Description

The problem describes the constraints on a student's work hours and earnings at a college. Students can work no more than 20 hours per week and can earn a maximum of 320perweek.Thejobspaydifferentrates,startingfrom320 per week. The jobs pay different rates, starting from 8.75 per hour. We need to write two inequalities representing these constraints and define the variables used.

2. Solution Steps

Let hh represent the number of hours a student works per week.
Let ee represent the amount a student earns per week.
The first constraint is that the student can work no more than 20 hours per week. This can be represented by the inequality:
h20h \le 20
The second constraint is that the student can earn a maximum of $320 per week. This can be represented by the inequality:
e320e \le 320
However, since the minimum rate is 8.75perhour,theearnings8.75 per hour, the earnings ewillbeequaltothenumberofhoursworked will be equal to the number of hours worked hmultipliedbythehourlyrate.Sinceweareconsideringtheminimumrate,andweknowthat multiplied by the hourly rate. Since we are considering the minimum rate, and we know that e \le 320,andsincetherateisatleast, and since the rate is at least 8.75$, we can have the following inequality:
8.75he3208.75h \le e \le 320. This implies that
8.75h3208.75h \le 320
Dividing both sides by 8.75, we have:
h3208.75h \le \frac{320}{8.75}
h36.57h \le 36.57
However, we are already given that h20h \le 20, which is stricter than h36.57h \le 36.57, so we use h20h \le 20.
The amount a student earns depends on the hourly rate multiplied by the number of hours worked. Let rr be the rate earned per hour.
Then e=rhe = r*h. Since the hourly rate is at least 8.75,8.75, r \ge 8.75$.
Also, the earnings are at most 320,so320, so e \le 320$.
A valid inequality to represent the income is: 8.75h3208.75h \le 320. If we divide both sides by 8.75, we get:
h3208.7536.57h \le \frac{320}{8.75} \approx 36.57.
However, we also have the constraint that h20h \le 20. So a better inequality is:
8.75he8.75h \le e, and e320e \le 320. Therefore, we can say that 8.75h3208.75h \le 320.
Since h20h \le 20, the maximum income should be 208.75=17520 \cdot 8.75 = 175.
The two inequalities are h20h \le 20 and e320e \le 320.
Alternatively, we can also use 8.75h3208.75h \le 320, if the rate is fixed at 8.75perhour.Inreality,thestudentcanhaveseveraljobswithdifferentrates.Let8.75 per hour. In reality, the student can have several jobs with different rates. Let h_ibethehoursworkedatjob be the hours worked at job iand and r_ibetherateforjob be the rate for job i.Thetotalnumberofhours. The total number of hours \sum h_i \le 20andtotalearnings and total earnings \sum r_i h_i \le 320.Iftherates. If the rates r_iwereall were all 8.75,then, then \sum 8.75 h_i = 8.75 \sum h_i \le 320$.
Since hi20\sum h_i \le 20, 8.75(20)3208.75(20) \le 320.

3. Final Answer

The two inequalities are:
h20h \le 20
e320e \le 320
where hh represents the number of hours a student works per week and ee represents the amount a student earns per week.

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