The problem asks to factor the expression $1-125x^3$ using the difference of cubes formula.

AlgebraFactoringDifference of CubesPolynomials
2025/3/25

1. Problem Description

The problem asks to factor the expression 1125x31-125x^3 using the difference of cubes formula.

2. Solution Steps

The expression is in the form of a3b3a^3 - b^3, where a3=1a^3 = 1 and b3=125x3b^3 = 125x^3.
Therefore, a=13=1a = \sqrt[3]{1} = 1 and b=125x33=5xb = \sqrt[3]{125x^3} = 5x.
The difference of cubes formula is:
a3b3=(ab)(a2+ab+b2)a^3 - b^3 = (a - b)(a^2 + ab + b^2).
Substituting a=1a=1 and b=5xb=5x into the formula, we have:
13(5x)3=(15x)(12+1(5x)+(5x)2)1^3 - (5x)^3 = (1 - 5x)(1^2 + 1(5x) + (5x)^2)
1125x3=(15x)(1+5x+25x2)1 - 125x^3 = (1 - 5x)(1 + 5x + 25x^2).

3. Final Answer

(15x)(1+5x+25x2)(1-5x)(1+5x+25x^2)

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