The problem asks us to factor the expression $64x^3 + 27$ using the sum of cubes formula.

AlgebraPolynomial FactorizationSum of CubesAlgebraic Manipulation
2025/3/25

1. Problem Description

The problem asks us to factor the expression 64x3+2764x^3 + 27 using the sum of cubes formula.

2. Solution Steps

The sum of cubes formula is:
a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a+b)(a^2 - ab + b^2)
In the given expression 64x3+2764x^3 + 27, we can rewrite it as (4x)3+(3)3(4x)^3 + (3)^3. Thus, we have a=4xa = 4x and b=3b = 3.
Applying the sum of cubes formula, we get:
(4x)3+(3)3=(4x+3)((4x)2(4x)(3)+(3)2)(4x)^3 + (3)^3 = (4x + 3)((4x)^2 - (4x)(3) + (3)^2)
Simplify the expression:
(4x+3)(16x212x+9)(4x + 3)(16x^2 - 12x + 9)

3. Final Answer

(4x+3)(16x212x+9)(4x+3)(16x^2-12x+9)

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