The problem asks us to factor the polynomial $x^3 + 11x^2 + 30x$ completely, if possible. If it cannot be factored, we should state that the polynomial is prime.

AlgebraPolynomial FactorizationFactoringQuadratic EquationsCubic Polynomials
2025/3/25

1. Problem Description

The problem asks us to factor the polynomial x3+11x2+30xx^3 + 11x^2 + 30x completely, if possible. If it cannot be factored, we should state that the polynomial is prime.

2. Solution Steps

First, we look for a common factor in all the terms of the polynomial. We can see that xx is a common factor.
Factoring out xx gives us:
x3+11x2+30x=x(x2+11x+30)x^3 + 11x^2 + 30x = x(x^2 + 11x + 30).
Now, we need to factor the quadratic expression x2+11x+30x^2 + 11x + 30.
We are looking for two numbers that multiply to 30 and add up to
1

1. These numbers are 5 and 6, since $5 \cdot 6 = 30$ and $5 + 6 = 11$. Thus, we can factor the quadratic as:

x2+11x+30=(x+5)(x+6)x^2 + 11x + 30 = (x + 5)(x + 6).
Putting it all together, the factored form of the original polynomial is:
x3+11x2+30x=x(x+5)(x+6)x^3 + 11x^2 + 30x = x(x + 5)(x + 6).

3. Final Answer

x(x+5)(x+6)x(x+5)(x+6)

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