First, simplify the term (ab3)2 using the power of a product rule: (xy)n=xnyn. (ab3)2=a2(b3)2=a2b6 Now substitute this back into the original expression:
[5a5b2×3a2b6]÷(15a2b8) Next, simplify the expression inside the brackets by multiplying the terms:
5a5b2×3a2b6=(5×3)(a5×a2)(b2×b6) Using the product of powers rule, xm×xn=xm+n: 15a5+2b2+6=15a7b8 Substitute this back into the expression:
[15a7b8]÷(15a2b8) Now, divide the two terms:
15a2b815a7b8 1515×a2a7×b8b8 1×a2a7×b8b8 Using the quotient of powers rule, xnxm=xm−n: a7−2b8−8=a5b0 Since b0=1, we have: a5×1=a5