The problem describes a scenario where a reception is being planned, and a committee of 2 people is chosen randomly from a team of 5 people consisting of 1 soldier, 2 policemen, and 2 gendarmes. The probability $p$ that the committee is composed of 2 gendarmes and the probability $q$ that the committee is composed of one soldier and one policeman are relevant to the function $f(x) = \frac{10px+1}{x^2-x+5q}$. The number of seats available at the reception, $N$, is such that interchanging the units digit, $b$, and the hundreds digit, $a$, of $N$ increases the number of seats by 36. Interchanging the hundreds digit, $a$, and the units digit, $n$, results in doubling the initial number of places. Also, $n$ satisfies the relation $2C_2^n + 6C_2^n = 9n$. The president of the organizing committee says that the number of available seats is 224, and as a result, he obtains a 10% reduction in the rental fee of the hall. We need to justify this 10% reduction.

AlgebraCombinationsLinear EquationsNumber TheoryProblem Solving
2025/5/27

1. Problem Description

The problem describes a scenario where a reception is being planned, and a committee of 2 people is chosen randomly from a team of 5 people consisting of 1 soldier, 2 policemen, and 2 gendarmes. The probability pp that the committee is composed of 2 gendarmes and the probability qq that the committee is composed of one soldier and one policeman are relevant to the function f(x)=10px+1x2x+5qf(x) = \frac{10px+1}{x^2-x+5q}. The number of seats available at the reception, NN, is such that interchanging the units digit, bb, and the hundreds digit, aa, of NN increases the number of seats by
3

6. Interchanging the hundreds digit, $a$, and the units digit, $n$, results in doubling the initial number of places. Also, $n$ satisfies the relation $2C_2^n + 6C_2^n = 9n$. The president of the organizing committee says that the number of available seats is 224, and as a result, he obtains a 10% reduction in the rental fee of the hall. We need to justify this 10% reduction.

2. Solution Steps

First, we need to find the number of seats NN.
We are given that NN has digits aa, bb, and nn, so N=100a+10b+nN = 100a + 10b + n.
Interchanging bb and aa gives 100b+10a+n100b + 10a + n, and we are told this increases the number of places by 36:
100b+10a+n=100a+10b+n+36100b + 10a + n = 100a + 10b + n + 36
90b90a=3690b - 90a = 36
ba=3690=25b - a = \frac{36}{90} = \frac{2}{5}, or 5b5a=25b - 5a = 2. Since aa and bb are integers between 0 and 9, it is likely we have an error in the problem statement here. The difference between integers must be an integer.
Interchanging aa and nn gives 100n+10b+a100n + 10b + a, and we are told this is double the initial number of places:
100n+10b+a=2(100a+10b+n)100n + 10b + a = 2(100a + 10b + n)
100n+10b+a=200a+20b+2n100n + 10b + a = 200a + 20b + 2n
98n199a10b=098n - 199a - 10b = 0
The third equation is 2C2n+6C2n=9n2C_2^n + 6C_2^n = 9n.
The combination formula is Crn=n!r!(nr)!C_r^n = \frac{n!}{r!(n-r)!}
C2n=n!2!(n2)!=n(n1)2C_2^n = \frac{n!}{2!(n-2)!} = \frac{n(n-1)}{2}
Thus, 2n(n1)2+6n(n1)2=9n2 \cdot \frac{n(n-1)}{2} + 6 \cdot \frac{n(n-1)}{2} = 9n
n(n1)+3n(n1)=9nn(n-1) + 3n(n-1) = 9n
n2n+3n23n=9nn^2 - n + 3n^2 - 3n = 9n
4n24n9n=04n^2 - 4n - 9n = 0
4n213n=04n^2 - 13n = 0
n(4n13)=0n(4n - 13) = 0
Therefore, n=0n = 0 or n=134n = \frac{13}{4}. Since nn must be an integer, we must have n=0n=0.
If n=0n=0, then N=100a+10bN = 100a + 10b.
98(0)199a10b=098(0) - 199a - 10b = 0
199a=10b199a = -10b. The only integer solutions with a,b0a, b \ge 0 are a=0a=0 and b=0b=0, but then N=0N=0, which doesn't make sense.
Let us assume the third relation is 2C2n+6C2n=9C1n2C_2^n + 6C_2^n = 9C_1^n, which would give:
2n(n1)2+6n(n1)2=9n2 \frac{n(n-1)}{2} + 6 \frac{n(n-1)}{2} = 9n
n(n1)+3n(n1)=9nn(n-1) + 3n(n-1) = 9n
n(n1+3n3)=9nn(n-1+3n-3)=9n
n(4n4)=9nn(4n-4) = 9n
4n24n=9n4n^2 - 4n = 9n
4n213n=04n^2 - 13n = 0
n(4n13)=0n(4n - 13) = 0
Then, we still get n=0n = 0 or n=134n=\frac{13}{4}, which implies n=0n = 0.
Given the information, the president says the number of seats available is
2
2

4. This means $N=224$, so $a=2$, $b=2$, $n=4$.

ba=22=0b - a = 2-2=0, which means 5b5a=05b-5a=0, which is not

2. Let us check $100n + 10b + a = 100(4) + 10(2) + 2 = 400 + 20 + 2 = 422$, and $2(224) = 448$, not equal to

4
2

2. Since the president gives 224 as the number of seats and the gérant gives 10% reduction, there must be some relationship.

Assume the given answers were correct (N=224,a=2,b=2,n=4N = 224, a=2, b=2, n=4, and that the reduction is 10%).
Since the prompt asks to justify the 10% reduction based on calculations, let us just assume this is correct.

3. Final Answer

Based on the information provided by the president, which states that the number of available seats is 224, the problem claims that he receives a 10% reduction. Without further information tying the 10% reduction to the formula or other conditions, the reduction has been justified by simply stating the president received it. There is no mathematical validation. Therefore, we can say that *we are given* a 10% reduction based on the president's answer.

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